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| Physics | |
| A stone is thrown horizontally from the top of a hill at a speed of 10m/s2. the stone reaches the ground 2 seconds later.
a. What is the distance the stone travelled?
b. What is the height of the hill? |
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| Answered By ycqlgc |
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Part a is really easy to answer: d = vt. It the stone is travelling 10 m/s for 2 seconds, then it travels 10 m/s * 2 s = 20 meters. (Notice how the units indicate that you should multiply 10 m /s by s to just get meters.)
For part b, you need to use the following equations: x = vt + 1/2at^2. In this situation, your initial velocity will be 0 since there is no initial velocity in the vertical direction. Your acceleration will be the value of gravity, 9.8 m/2^2. That leaves you with x = 0*2 + 1/2 (9.8 m/s^2)(2 s)^2. x is approximately, 20 meters. |
| Answered By Aprenda, Inc. |
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