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| Chemistry | |
| when 0.600 g of Naoh is dissolved in 100.0 g water, temp rises from 25.00 to 25.98 C, calculate the amount of heat generated |
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| 2 Answers |
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| Answered By utyzul |
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for water dH = m C dT dH = 100.0 grams (4.184 J/g.C) (0.98 C) dH = 410. Joules absorbed
410 Joules were produced (written with 2 sig figs, since that's all the dT had)
============================== usually we include the mass of the NaOH in with the 100.0 grams of water, which changes your rough calcs:
for water dH = m C dT dH = 100.6 grams (4.184 J/g.C) (0.98 C) dH = 4102 Joules absorbed
410 Joules were produced (written with 2 sig figs, since that's all the dT had) ======================================…
p.s. find moles NaOH using molar mass 0.600 g NaOH @ 40.00 g/mol = 0.015 molesNaOH
find Heat released per mole of NaOH dissolved: 410 Joules / 0.015 moles = 27,333 Joules / mole NaOH 27.3 kJ /mol NaOH
text book is 44kJ/mol |
| Answered By Steve O |
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