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| Chemistry | |
okay, I need help with these, plzz help! please balance them, some may already be balanced, i dont get this crap!!
14.)Al(OH)3+H2CO3 =>Al2(CO3)3=H2O
18.)Rb=RbNO3 => Rb2O=N2
19.)C6H6+O2 => CO2+H20
21.)C10H22+O2 => CO2+H2O
22.)Al(OH)3+HBr => AlBr3+H2O
23.)CH3CH2CH2CH3+O2 => CO2=H20
24.)C+O2 => CO2
25.)C3H8+O2 => CO2+H20
26.)Li+AlCl3 => LiCl+Al
27.)C2H6+O2 => CO2 +H20
28.)NH4OH+H3PO4 => (NH4)3PO4+H20
39.)Fes2+O2 => Fe2O3+SO2
*NOTE: THE NUMBERS ARE SMALL, THE COMPUTER COUNLDNT MAKE EM' SMALL, THANKS!!)
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| 5 Answers |
Asked By IanKusek |
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| Answered By yakddoge |
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| Answered By jptbbtseu |
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To balance these equations, first balance the number of atoms on each side of the equation. For example, #14:
Al(OH)3 + H2CO3 ---> AL2(CO3)3 + H2O
Since there are twice as many aluminums on the right side, put a 2 before AL(OH)3
2 Al(OH)3 + H2CO3 ---> AL2(CO3)3 + H2O
and you have 3x as many carbonate ions on the right side, so put a three before H2CO3
2 Al(OH)3 + 3 H2CO3 ---> AL2(CO3)3 + H2O
now, you have 6 OH-'s and 6 H+s which come together to make 6 H2Os.
2 Al(OH)3 + 3 H2CO3 ---> AL2(CO3)3 + 6 H2O
voila. a properly balanced chemical equation.
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| Answered By Aprenda, Inc. |
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